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namespace.py
# # DBus names and paths # # Copyright (C) 2019 Red Hat, Inc. All rights reserved. # # This library is free software; you can redistribute it and/or # modify it under the terms of the GNU Lesser General Public # License as published by the Free Software Foundation; either # version 2.1 of the License, or (at your option) any later version. # # This library is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU # Lesser General Public License for more details. # # You should have received a copy of the GNU Lesser General Public # License along with this library; if not, write to the Free Software # Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 # USA# __all__ = [ "get_dbus_name", "get_dbus_path", "get_namespace_from_name" ] def get_dbus_name(*namespace): """Create a DBus name from the given names. :param namespace: a sequence of names :return: a DBus name """ return ".".join(namespace) def get_dbus_path(*namespace): """Create a DBus path from the given names. :param namespace: a sequence of names :return: a DBus path """ return "/" + "/".join(namespace) def get_namespace_from_name(name): """Return a namespace of the DBus name. :param name: a DBus name :return: a sequence of names """ return tuple(name.split("."))